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=81-0.01P^2
We move all terms to the left:
-(81-0.01P^2)=0
We get rid of parentheses
0.01P^2-81=0
a = 0.01; b = 0; c = -81;
Δ = b2-4ac
Δ = 02-4·0.01·(-81)
Δ = 3.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{3.24}}{2*0.01}=\frac{0-\sqrt{3.24}}{0.02} =-\frac{\sqrt{}}{0.02} $$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{3.24}}{2*0.01}=\frac{0+\sqrt{3.24}}{0.02} =\frac{\sqrt{}}{0.02} $
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